2/4.9=t^2

Solution for 2/4.9=t^2 equation:

2/4.9=t^2

We move all terms to the left:

2/4.9-(t^2)=0

We add all the numbers together, and all the variables

-1t^2+2/4.9=0

We multiply all the terms by the denominator


-1t^2*4.9+2=0

Wy multiply elements

-4.9t^2+2=0

a = -4.9; b = 0; c = +2;
Δ = b2-4ac
Δ = 02-4·(-4.9)·2
Δ = 39.2
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-\sqrt{39.2}}{2*-4.9}=\frac{0-\sqrt{39.2}}{-9.8}
=-\frac{\sqrt{}}{-9.8}
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+\sqrt{39.2}}{2*-4.9}=\frac{0+\sqrt{39.2}}{-9.8}
=\frac{\sqrt{}}{-9.8}
$